Группа 002402
Профи
(518)
10 лет назад
1 вариант
1а = х^2*(3+x)
1b =4*(4*x^2-1)=4*(2x+1)*(2x-1)
1c = 2*(x+3)+x*(x+3)=(x+3)*(x+2)
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2) x*(2x+3)=0
x1=0 x2=3/2=1.5
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3) 5*b/c
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4)a^2+2*a*b+b^2-2*a*b+a^2-b^2=2*a^2
a^2+a^2=2*a^2 чтд
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5)x^2*(x+1)-4*(x+1)=0
(x^2-4)*(x+1)=0
(x-2)*(x+2)*(x+1)=0
x1=-1 x2=2 x3=-2
2 вариант
1а = x^3*(x+1)
1b =2*(a^2-4)=2*(a-2)(a+2)
1c = x*(x+1)+2*(x+1)=(x+1)*(x+2)
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2)x*(3-x)=0
x1=0 x2=3
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3)=2*a*c
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4)a^2-2*a*b+b^2-2*a*b+2*a^2-b^2=a*(3*a-4*b)
3*a^2-4*a*b=a*(3*a-4*b)
a*(3*a-4*b)=a*(3*a-4*b) чтд
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5) x^2*(2*x+1)-4*(2*x+1)=0
(x^2-4)*(2*x+1)=0
(x-2)*(x+2)*(2*x+1)=0
x1=2 x2=-2 x3=0.5