Алексей Лукьянов
Высший разум
(179337)
3 года назад
2(sinx)^2 + sin x – 1 = 0, sinx = 1/2, x = (– 1)^k*(π/6) + πk, k∈Z
4(sinx)^2 + 11sin x – 3 = 0, sinx = 1/4, x = (– 1)^k*arcsin(1/4) + πk, k∈Z
6(cosx)^2 + cosx – 1 = 0, cosx = – 1/2, cosx = 1/3, x1 = ±2π/3 + 2πk, x2 = ±arccos(1/3)+ 2πk, k∈Z
8(sinx)^2 – cos x + 1 = 0, –8(cosx)^2 – cos x + 9 = 0, cosx = 1, x = 2πk, k∈Z
6cos ^2 x + cosx-1=0
8sin^2 x - cos x +1 = 0