2cos*2x+2sinx=2,5

Ответ. 2*cos(2*x)+2*sin(x)=2,5; 4*(cos(x))^2-4*(sin(x))^2+2*sin(x)-2,5*(sin(x))^2-2,5*(cos(x))^2=0;
1,5*(cos(x))^2-6,5*(sin(x))^2+2*sin(x)=0; 1,5-8*(sin(x))^2+2*sin(x)=0; sin(x1)=0,576; sin(x2)=-0,326;