Natali Belska
Просветленный
(36159)
1 год назад
4^x - 3^(x-0,5) = 3^(x+0,5) - 2^(2x-1)
(4^x + 4^x/2) = 3^x/3^(0,5) + 3^x * 3^(0,5)
4^x * 3/2 = 3^x * (V3 + 1/V3)
4^x / 3^x = 4/V3 / 3/2 = 4/V3 * 2/3 = 2/V3 = 4^(1/2) / 3^(1/2)
(4/3)^x = (4/3)^(1/2)
x = 1/2 = 0,5