Natali Belska
Просветленный
(36291)
2 года назад
{ (x-8)(y-9) = 0
{ (y-5)/(x+y-13) = 4 ----> ОДЗ: (x+y-13) не= 0
=>
(x-8) = 0 -----> x = 8
(y-9) = 0 -----> y = 9
a) x = 8 =>
(y-5)/(8+y-13) = 4
(y-5)/(y-5) = 4 - не удовл. условию
б) y = 9
(9-5)/(x+9-13) = 4
4/(x-4) = 4
(x-4) = 1
x = 5
Проверка по ОДЗ: (5+9-13) = 1
Ответ: х = 5; y = 9