Найдите корень уравнения (х-2)^2 =(х-9)^2

Question

vakhit_vagizovich · Accepted Answer

(х-2)^2 =(х-9)^2
x^2 -4x+4= x^2 -18x+81
-4x+18x= 81-4
14x= 77
x= 77/14= 11/2= 5,5

user_299633955 · Answer

(X^2) - 4x + 4 = (x^2)-18x+81
-4x+4=-18x+81
14x = 77
x = 5,5
Ответ:5,5

ktoto_kakoito_212 · Answer

X2 - 4x + 4 = x2 - 18x + 81
14x = 77
X = 5,5

nadezhda_36028 · Answer

|x-2|=|x-9|
x-2=x-9
корней нет
x-2=9-x
2x=11
x=5,5

natali_belska_3 · Answer

(х-2)^2 = (х-9)^2
(х-2)^2 - (х-9)^2 = 0
[(x-2) - (x-9)] * [(x-2) + (x-9)] = 0
7 * (2x - 11) = 0
2x - 11 = 0
x = 11/2
Проверка:
(11/2 - 2)^2 = (11/2 - 9)^2
(11 - 4)^2/4 = (11 - 18)^2/4
7^2 = (-7)^2
49 = 49

artur_muftaliev · Answer

X