Pharaon Ramzes
Мастер
(1998)
15 лет назад
(x^2-1)^(1/6) = ((x+1)(x-1))^(1/6) = (x+1)^(1/6)*(x-1)^(1/6)
Разделим обе части на (x+1)^(1/6)*(x-1)^(1/6):
(x+1)^(1/6)/(x-1)^(1/6) - (x-1)^(1/6)/(x+1)^(1/6) = 1. Замена y=(x+1)^(1/6)/(x-1)^(1/6):
y+1/y=1.
Дальше сам.