SQL задачка на логику

 WITH grouped_user_ids AS (  
  ClientID 
  , COUNT(*) AS orders_count
  FROM Orders 
  WHERE DATE_TRUNC('year', OrderDate) = 2015
  GROUP BY ClientID
)
SELECT
  c.LastNAme
  , c.FirstName
  , g.orders_count
FROM grouped_user_ids AS g
JOIN Client AS c
ON g.ClientID = c.ClientID
WHERE g.orders_count > 25
ORDER 3 DESC;