Очено срочно помогите пожалуйста

1)а) = X^0,9*X^1,1=x^2; б) = √х/√х = x^0 = 1;

2)а) =( 2^3)^(2/3)*2^(1/2)/2^(-1/2) = 2^3= 8;

б)=(( 5^2)^(-1/4)*5^(-1/2))^(-1) =( 5^(-1))^(-1) = 5

3) = а^(2/3) - b^2 - a^(2/3) = - b^2

4)= ( x^(1/2) +1)*x^(1/4)*(x^(1/4) -1)*x^(1/4)/ (x^(1/2)*(x^(1/4) - 1) ) - 1

=x^(1/2) + 1 - 1 = x^(1/2)