Сколько будет 7 root(5)(7)⋅ 4/50 ⋅ (40 root(4)(5))/70^(8 root(7)(5)) ⋅ root(9)(20⋅5 7/4 )

7 * 7^(1/5) * 4/50 * [40 * 5^(1/4) / 70^8 * 5^(1/7)] * (20 * 5 7/4)^(1/9) =

__ 7 * 7^(1/5) = 7^(1+1/5) = 7^(6/5)
__ 4/50 = 2^2 / 2 * 5^2 = 2 / 5^2
__ 40 = 2^3 * 5
__ 70^8 = (5*2*7)^8 = 5^8 * 2^8 * 7^8
__ 20 = 2^2 * 5
__ 5 7/4 = 27/4 = 3^3 / 2^2
=>
= 7 * 7^(1/5) * (2 / 5^2) * [(2^3 * 5) * 5^(1/4) / (5^8 * 2^8 * 7^8) * 5^(1/7)] * [(2^2 * 5) * (3^3 / 2^2)]^(1/9) = решай