Centurio
Просветленный
(30635)
1 неделю назад
Z = R1+(XL-XC)j = 5+(20-8)j = 5+12j = 13*e^(67,38j) Ом
cos(phi) = 12/5 = 2,4
I = U/Z = 260/(13*e^(67,38j)) = 20*e^(-68,38j) A
S = 260*20*e^(68,38j) = 5200*e^(68,38j) = 2000+4800j BA
P = 2000 Вт
Q = 4800 BAp