Евгений Криворотько
Ученик
(177)
1 день назад
Я прогнал через нейронку вот ответ
To solve the nuclear reaction equation \(_3^6Li + _1^1p \rightarrow ? + \alpha\), we need to determine the missing particle.
The reaction can be written as:
\[ _3^6Li + _1^1p \rightarrow ? + _2^4He \]
Here, \(\alpha\) (alpha particle) is \(_2^4He\).
1. **Atomic numbers (proton numbers) balance**:
The sum of atomic numbers on the left must equal the sum of atomic numbers on the right.
\[ 3 (Li) + 1 (p) = 4 (He) + Z_{?} \]
\[ 4 = 4 + Z_{?} \]
\[ Z_{?} = 0 \]
2. **Mass numbers (nucleon numbers) balance**:
The sum of mass numbers on the left must equal the sum of mass numbers on the right.
\[ 6 (Li) + 1 (p) = 4 (He) + A_{?} \]
\[ 7 = 4 + A_{?} \]
\[ A_{?} = 3 \]
The particle must have an atomic number \(Z = 0\) and a mass number \(A = 3\), which corresponds to \(_0^3He\), also known as a tritium (\(^3He\)).
The correct answer is:
\[ \boxed{1 \text{ } _2^3He} \]