Помогите срочно с дробью в математике

4(3224¹⁰⁰+1)²+2(3224¹⁰⁰-2)² - 2(3224²⁰⁰+8)/((3224¹⁰⁰+1)²-3224¹⁰⁰ - 3224²⁰⁰)(3224¹⁰⁰ - 1)
4(3224¹⁰⁰+1)²+2(3224¹⁰⁰-2)² - 2(3224²⁰⁰+8) =
4*(a+1)^2 + 2*(a-2)^2 - 2*(a^2+8) = 4*(a-1)*(a+1)
((3224¹⁰⁰+1)²-3224¹⁰⁰ - 3224²⁰⁰)(3224¹⁰⁰ - 1)
= ( (a+1)^2 - a - a^2 )*(a-1) = (a+1)*(a-1)
4*(a-1)*(a+1)/ ( (a+1)*(a-1) ) = 4


4(3224¹⁰⁰+1)²+2(3224¹⁰⁰-2)² - 2(3224²⁰⁰+8)/((3224¹⁰⁰+1)²-3224¹⁰⁰ - 3224²⁰⁰)(3224¹⁰⁰ - 1) = 4