S.H.I.
Оракул
(68554)
1 месяц назад
3x − 4·0 + 24 = 0
3x + 24 = 0
3x = −24
x = −8
3·0 − 4y + 24 = 0
−4y + 24 = 0
−4y = −24
y = 6
x₁ = −8, y₁ = 0
x₂ = 0, y₂ = 6
x₃ = 0, y₃ = 0
S = (1⁄2) ⋅ | x₁(y₂ − y₃) + x₂(y₃ − y₁) + x₃(y₁ − y₂) |
S = (1⁄2) ⋅ [ (−8)(6 − 0) + 0(0 − 0) + 0(0 − 6) ]
S = (1⁄2) ⋅ [ (−8)(6) ]
S = (1⁄2) ⋅ (−48)
S = 24