Помогите с решением примера! Кто может решить?

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3^(1/3) * (3 * 3^(1/3))^(1/2) / (9^(1/4) - 1)(9^(1/4) + 1) =

= 3^(1/3) * (3^(1+1/3))^(1/2) / [(9^(1/4))^2 - 1^2] =

= 3^(1/3) * (3^(4/3)^(1/2) / [(9^(2 * 1/4)) - 1] =

= 3^(1/3) * (3^(4/3 * 1/2)) / [(9^(1/2)) - 1] =

= 3^(1/3) * (3^(2/3)) / (3 - 1) =

= 3^(1/3 + 2/3) / 2 =

= 3^1 / 2 = 3/2


27^(1/3) : 3^(-1) - 2^(-4) * 64^(1/3) =

= (3^3)^(1/3) : 1/3 - 1/2^4 * (2^6)^(1/3) =

= 3^(3 * 1/3) * 3/1 - 2^(6 * 1/3)/ 2^4 =

= 3^1 * 3 - 2^2/2^4 =

= 9 - 1/2^2 = 9 - 1/4 = 8 + 4/4 - 1/4 = 8 + 3/4 = 8 3/4