Парсинг сайта(название и описание)

 import requests 
from bs4 import BeautifulSoup as BS 
import xlsxwriter 
 
 
page = 1 
 
rek = ('https://xn--80aaig9ahr.xn--c1avg') 
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/131.0.0.0 Safari/537.36'} 
data = [['Наименование', 'Описание']] 
 
 
def get_sol(url): 
   res1 = requests.get(url, headers) 
   return BS(res1.text, 'html.parser') 
 
 
 
while True: 
    res = requests.get("https://xn--80aaig9ahr.xn--c1avg/manga?page=" + str(page), 
                       "&content=manga&categories=63&count_chapters_gte=20&count_chapters_lte=5000") 
    soup = BS(res.text, 'html.parser') 
    headlines = soup.find_all('a', class_='Vertical_card__Qez7E') 
 
 
    if(len(headlines)): 
        for cat in headlines: 
            name = cat.text 
            subcategories = get_sol(rek + cat['href']) 
            for manga in subcategories: 
                title = manga.find('div', class_='Typography_body1__YTqxB').find(text=True).strip() 
                data.append([name, title]) 
        page += 1 
    else: 
        break 
 
 
with xlsxwriter.Workbook('manga.xlsx') as workbook: 
    worksheet = workbook.add_worksheet() 
 
    for row_num, info in enumerate(data): 
        worksheet.write_row(row_num, 0, info) 
 

line 31, in <module> title = manga.find('div', class_='Typography_body1__YTqxB').find(text=True).strip() ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ TypeError: find() takes no keyword arguments