Решите задания по логарифмическим функциям

а) -3 - (-3) = 0
б) log(12)12 = 1
с) 3^(log (3) 16) = 16 (если там в основании 3)

log(1/2) 8 - log(1/3) 27 = =>
__ log(1/2) 8 =
= log(1/2) (1/8)^(-1) =
= log(1/2) ((1/2)^(-3)) =
= (- 3) * log(1/2) (1/2) = (-3)*1 = - 3
__ log(1/3) 27 =
= log(1/3) (1/27)^(-1) =
= log(1/3) ((1/3)^(-3)) =
= (-3) * (log(1/3) (1/3) = (-3)*1 = - 3
=>
= (-3) - (-3) = 0

log12 3 + log12 4 = log12 (3*4) = log12 (12) = 1

3^(2*log3 4) = 3^(log3 (4^2)) = 3^(log3 16) = 16