Помогите пожалуйста с логарифмическим неравнеством.

[log2 (2-x)]^2 - 8*log(1\4) (2-x) >= 5 ...ОДЗ: (2-x) > 0 -----> x < 2

___ log(1\4) (2-x) = log(2^(-2)) (2-x) = 1\(-2) * log2 (2-x) = -1\2 * log2 (2-x)
=>
[log2 (2-x)]^2 - 8 * (-1\2) *log2 (2-x) >= 5

[log2 (2-x)]^2 + 4 *log2 (2-x) >= 5 ...log2 (2-x) = t

t^2 + 4*t - 5 >= 0

(t -1)(t + 5) >= 0 --------> t =< -5 или t >= 1
t =< -5 ------> log2 (2-x) =< -5 -----> log2 (2-x) =< log2 2^(-5) ----> 2-x =< 2^(-5) ---> x >= 2-2^(-5)
t >= 1 -------> log2 (2-x) >= 1 ------> log2 (2-x) >= log2 2 ----------> 2-x >= 2 ---------> x =< 0