Помогите решить задачу по физике

s(t) = (1/2)at²
ma = mg - T
ma = mg - (1/2)Mε
ma = mg - (1/2)M(a/R)
a = (2mgR) / (2mR + MR) = (2 * 1 * 9.8 * 0.05) / (2 * 1 * 0.05 + 10 * 0.05) ≈ 0.182 м/с²
T = (1/2)Mε = (1/2)M(a/R) = (1/2) * 10 * (0.182 / 0.05) ≈ 18.2 Н
φ(t) = (1/2)εt² = 1.82t² рад
ω = εt = 3.64 * 1 = 3.64 рад/с
aτ = εR = 3.64 * 0.05 = 0.182 м/с²
an = ω²R = 3.64² * 0.05 ≈ 0.663 м/с²