Алебра 10-11 класс

2/x^3- 8 ^4 корень из х;
(x)' = (2x^4 – x^2 + 1)’ = (2x^4)’ – (x^2)’ + (1)’ = 2 * 4 * x^(4 – 1) – 2 * x^(2 - 1) – 0 =
8 * x^3 – 2 * x^1 = 8x^3 – 2x.
f(x)' = ((1/2) * x^2 – (1/5) * x^5)’ = ((1/2) * x^2)’ – ((1/5) * x^5)’ = (1/2) * 2 * x^(2 - 1) – (1/5) * 5 * x^(5 - 1) = 1 * x^1 – 1 * x^4 = x – x^4.
f(x)' = (x^2 - 3x + 1)’ = (x^2)’ – (3x)’ + (1)’ = 2 * x^(2 – 1) – 3 * x^(1 - 1) – 0 = 2x – 3.
f(x)' = (3 – 2x + 4x^2 – 7x^3)’ = (3)’ – (2x)’ + (4x^2)’ – (7x^3)’ = 0 – 2 * x^(1 – 1) + 4 * 2 * x^(2 - 1) – 7 * 3 * x^(3 – 1) = -2 * x^0 + 8 * x^1 – 21 * x^2 = -2 + 8x – 21x^2.