Помогите найти контрольную

=4*sqrt(2)*sqrt(2)/2*1/2=2

y'=(-4(7x+5)-7(3-4x))/(7x+5)^2=(-28x-20-21+28x)/(7x+5)^2=-41/(7x+5)^2
y'(0)=-41/25=-1,64

2sin x+sqrt(3)=0
2sin x=-sqrt(3)
sin x=-sqrt(3)/2
x=4pi/3+2*pi*n

tg 240=tg(180+60)=tg 60=sqrt(3)

y'=-x/sqrt(5-x^2)
y'(1)=-1/2

(cos^2 10+cos^2 80)/(sin^2 61+sin^2 29)=(cos^2 10+cos^2 (90-10))/(sin^2 (90-29)+sin^2 29)=(cos^2 10+sin^2 10)/(cos^2 29+sin^2 29)=1/1=1

y'=3sqrt(x)+3/2*x/sqrt(x)-2
y'(1)=3+3/2-2=5/2=2,5

y'=6/cos^2 (3x+pi/3)
y'(0)=6/cos^2 pi/3=6:1/4=6*4=24

cos^2 a/(cos^3 a*sin a+cos a*sin^3 a)=cos^2 a/(cos a*sin a*(cos^2 a+sin^2 a)=cos^2 a/(cos a*sin a)=cos a/sin a=ctg a

tg a=-sin a/cos a=-sin a/sqrt(1-sin^2 a)=-8/17/sqrt(1-64/289)=-8/17/15/17=-8/17*17/15=-8/15

y'=9x^2-8x
y(4)=123
y'(4)=112
y=123+112*(x-4)=123+112x-448=112x+325

cos x=-1/2
x=4pi/3+2*pi*n
xmin=4pi/3

sin(-a)*cos(pi/2+a)/(cos(-a)*cos(pi-a))=-sin a*(-sin a)/(cos a*(cos a))=-sin^2 a/cos^2 a=-tg^2 a

y'=2+12/x^3
y'(1)=2+12=14

f'(x)=3*(6x-2)^2+6x(6x-2)=3(36x^2-24x+4)+36x^2-12x=144x^2-84x+12
f'(0)=12

cos^4 a+sin^2 a*cos^2 a=cos^2 a(cos^2 a+sin^2 a)=cos^2 a