Физика - Прошу помочь решить задачу.

Question

Физика - Прошу помочь решить задачу.

Алексей Митин Ученик (90), на голосовании 6 лет назад

Прошу помочь решить задачу.

По двум параллельным проводникам текут токи силой 70 и 80 А. Расстояние
между проводниками - 1,4 см. С какой силой взаимодействуют провода на каждый
метр длины?

Answer 1

Ответ. 3. i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;
Источник: физика

Answer 2

. i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;
Наверно я там

Answer 3

Ответ. 3. i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;

Answer 4

Ответ. 3. i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;
Источник: физика

Answer 5

i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;

Answer 6

Ответ. 3. i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;
Источник: физика

Answer 7

i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;

Answer 8

Ответ. 3. i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;

Answer 9

Илья Малахов Знаток (276) 6 лет назад

я не знаю

Answer 10

Ответ. 3. i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t)

Answer 11

Ответ. 3. i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;

Answer 12

Ответ. 3. i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;

Answer 13

Ответ. 3. i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;

Answer 14

Руслан Кухтенко Гуру (2942) 6 лет назад

Сколько же тут копипастеров!

Answer 15

i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;

Answer 16

[f[ff[f[[f vot i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;

Answer 17

i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;

Answer 18

Миша косарев Ученик (219) 6 лет назад

это какой класс

Answer 19

i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;

Answer 20

i*R+L*di/dt=0; di/i=-(R/L)*dt; Ln(i(t))=Ln(C)-(R/L)*t; i(t)=C*e^(-(R/L)*t); C=J0; i(t)=J0*e^(-(R/L)*t); J0/J(t)=e^((R/L)*t); (R/L)*t=Ln(J0/J(t)); t=0,01; R=23; J0/J(t)=10; L=(R*t)/(Ln(10)); L=0,1;