Как решить? помогите пожалуйста

1) System of Inequalities: x - 4 0, 2x = -6

To solve this system, we'll first convert the second equation into a slope-intercept form (y = mx + b).

2x = -6
x = -3

Now, we have two lines:
x - 4 = 0 and y = -3 (x = -3)

Since the lines don't intersect, there's no solution to this system of inequalities.

2) System of Inequalities: x - 2 3, -3x - 12

First, let's write the inequalities in the slope-intercept form (y ≥ mx + b):

x - 2 3 → y ≥ 3x - 6
-3x - 12 → y ≥ 3x + 4

Now, we'll graph these lines and find the region where both inequalities are satisfied.

3) System of Inequalities: x + 6 2, x/4 2

First, let's write the inequalities in the slope-intercept form (y ≥ mx + b):

x + 6 2 → y ≥ -2x + 12
x/4 2 → y ≥ 4x

Now, we'll graph these lines and find the region where both inequalities are satisfied.

4) System of Inequalities: 6x + 3 = 0, 7 - 4x 7

First, let's solve the equation 6x + 3 = 0 for x:

6x = -3
x = -1/2

Now, substitute this value of x into the second inequality:

7 - 4(-1/2) 7
7 + 2 7

Since this is true, the solution to this system of inequalities is x = -1/2.

5) System of Inequalities: 10x - 1 3, 7 - 3x 2x - 3

First, let's write the inequalities in the slope-intercept form (y ≥ mx + b):

10x - 1 3 → y ≥ 10x - 4
7 - 3x 2x - 3 → y ≥ 5x - 10

Now, we'll graph these lines and find the region where both inequalities are satisfied.

6) System of Inequalities: x - 2 1 + 3x, 5x - 7 = x + 9

First, let's solve the equation 5x - 7 = x + 9 for x:

4x = 16
x = 4

Now, substitute this value of x into the first inequality:

4 - 2 1 + 3(4)
2 7

Since this is true, the solution to this system of inequalities is x = 4.