Sergio 2.1
Оракул
(64004)
2 недели назад
1.
limₙ→∞ (3n +1)/(2n +1) = 3/2
| (3n +1)/(2n +1) - 3/2 | = 1/(4n +2) < ε
4n +2 > 1/ε ⇒ n > (1/ε -2)/4
N = ⌈(1/ε -2)/4⌉
2.
a)
limₙ→∞ (4n² +3n +1)/(2n² -1) = 2
b)
limₙ→∞ √(4n² +n +1) -2n = 1/4
c)
limₙ→∞ cos²(n +1)/(n +10) = 0
d)
limₙ→∞ ((n +1)/(n -1))ⁿ = e²
3.
а)
limₓ→-1 (x² -x -2)/(x³ +1) = -1
б)
limₓ→∞ (x³ +2x² +3x +4)/(4x³ +3x² +2x +1) = 1/4
в)
limₓ→0 (√(1 +x +x²) -1)/x = 1/2
д)
limₓ→0 (sin5x)/(sin3x) = 5/3
г)
limₓ→3 [1/(x -3) -x/(x² -9)] =
→3⁺: +∞
→3⁻: -∞
е)
limₓ→∞ ((x² +1)/x²)^(x² -1) = e
4.
f(x) = (x² -4)/(x² -2)
x = √2, -√2
5.
[(x -1)(x² +4x)(x -2)²]/(x² -9) ≤ 0
[(x -1)·x·(x +4)·(x -2)²]/[(x -3)(x +3)] ≤ 0
x = -4, -3, 0, 1, 2, 3
(-∞, -4] ∪ (-3, 0] ∪ [1, 3)