S.H.I.
Оракул
(68482)
1 месяц назад
1) ((81^(1/4 - 1/2 log_9 4) + 25^log_25 8) * 49^log_7 2)
81 = 3^4, 25 = 5^2, 49 = 7^2
(3^4)^(1/4 - 1/2 log_9 4) = 3^(4(1/4 - 1/2 log_9 4)) = 3^(1 - 2 log_9 4)
2 log_9 4 = 2 * (log_3 4 / log_3 9) = 2 * (log_3 4 / 2) = log_3 4
3^(1 - log_3 4) = 3/4
25^log_25 8 = 8
3/4 + 8 = 35/4
49^log_7 2 = (7^2)^log_7 2 = 7^(2 log_7 2) = 2^2 = 4
35/4 * 4 = 35
Ответ: 35
2) 6^(log_6 5 + 1) - 25
6^(log_6 5 + 1) = 6^log_6 5 * 6 = 5 * 6 = 30
30 - 25 = 5
Ответ: 5