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It seems like you're referencing a circuit involving resistors, likely in a specific configuration, but the information you've provided is somewhat ambiguous. To assist you better, I’ll provide a general overview of how to analyze a circuit with resistors and create connections based on the labels provided.

Assuming:
- R1 = 1 ohm
- R2 = 2 ohms
- R3, R4, R5, R6, R7, R8 have unspecified values

Let's first clarify the symbols:
- A, B, and G could be nodes in your circuit.
- The connections between them (like AB, BG, etc.) imply possible series or parallel combinations of resistors.

### Steps to Compute Equivalent Resistances

1. **Identify Connections:**
- Determine which resistors are connected to each other at the given nodes (A, B, and G).

2. **Series and Parallel Combinations:**
- Series: If resistors are connected end-to-end, their resistances add up:
\[
R_{eq} = R_1 + R_2 + ... + R_n
\]
- Parallel: If resistors are connected across the same two nodes, the equivalent resistance \( R_{eq} \) can be found using:
\[
\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}
\]

3. **Solve for Each Connection:**
- **R АБ (between A and B)**: Look for resistors directly between nodes A and B, or series/parallel combinations leading to it.
- **R АВ (between A and V)**: Similarly, calculate based on the configuration between A and V (assuming V is another node).
- **R ВГ (between B and G)**: Identify resistors directly connected or those that can be combined to find this resistance.
- **R БГ (between B and G)**: Find the total resistance as done before.
- **R АГ (between A and G)**: Again, perform the necessary calculations based on the resistors connected to these nodes.

### Example Calculation
If you provide specific connections for:
- R1, R2, …, R8
- The exact circuit configuration

I could help with concrete values and calculations for each of those connections. Please clarify any additional information or context around your circuit so that I can assist you more accurately!
На переведи джпети чат только так считает на буржуйском

1. Считаем R(АБ): "растянем" цепь за точки А и Б немного и увидим, что она стала цепью из двух параллельных веток, в верхней последовательно R1 и R2, a в нижней последовательно — все остальные. Считаем R верхней ветви: Rв = R1 + R2 = 1+2 = 3 Ом. Для нижней ветви: Rн = 3+4+5+6+7+8 = 33 Ом. Но Rв и Rн параллельны друг другу, значит R(АБ) = Rв*Rн/(Rв+ Rн) (*) = 3*33/(3+33) = 2.75 Ом.
2. Дальше — сам справишься. В диагональном случае (R(АГ) в параллельных ветвях будет поровну, по четыре, сопротивлений, но принцип решения одинаковый: в каждой ветви просто складываешь Ri, а дальше - по формуле (*).
3. .......