Математика огэ 20 задание 2 часть

Question

otriad_13 · Accepted Answer

(x-4)(x+3)² = 8(x+3)
8 = (x-4)(x+3)²/(x+3)
8=(x-4)(x+3)
8 = x² - 4x + 3x - 12
x² - x - 12 - 8 = 0
x² - x - 20 = 0
D = 1 + 80 = 81
x1 = (1 + 9)/2 = 5
x2 = (1-9)/2 = -4

pomogay · Answer

помогаю

aksioma_6 · Answer

( x- 4)(x+3)²-  8(x+3) =0. ___ общий множитель( х +3) за скобку,
( x+ 3)( (x-4)(x+ 3)- 8) = 0;
( x+ 3)( x² - x  - 20) = 0;
1) x+3 = 0 => x1 = -3;
2) x² - x - 20= 0,
D= 81 =>
x2= - 4, x3 = 5.
Ответ: -4; -3; 5.